By Max Hailperin
This article covers the fundamentals of programming and knowledge constructions, and provides first-time machine technology scholars the chance not to in simple terms write courses, yet to end up theorems and research algorithms to boot.
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Additional info for Concrete abstractions : an introduction to computer science using Scheme
The fundamental problem with this procedure is, it tries to always leave one multiplication for last, even when there are none to be done. Computing 1! doesn’t require any multiplications; the answer is simply 1. What we can do is treat this base case specially, using if, just like in the human program for making chains: (define factorial (lambda (n) (if (= n 1) 1 (* (factorial (- n 1)) n)))) (factorial 52) 80658175170943878571660636856403766975289505440883277824000000000 000 Thus, base cases are treated separately in recursive procedures.
At that point, the spiraling stops, because we’ve known since the very beginning that square could square 0. The key point that makes this spiral reasoning work is that the chain of reasoning leads inexorably down to the base case of zero. We only defined square in terms of smaller squares, so there is a steady progression toward the base case. By contrast, even though it is equally true that n2 ϭ (n ϩ 1)2 Ϫ (2n ϩ 1), the following procedure does not correctly compute the square of any positive integer: (define square ; This version doesn’t work.
A built-in procedure called remainder finds the remainder; for example, (remainder 1234 10) evaluates to 4. 9 Write a procedure that computes the number of 6s in the decimal representation of an integer. Generalize this to a procedure that computes the number of d’s, where d is another argument. 10 Write a procedure that calculates the number of odd digits in an integer. 11 Write a procedure that computes the sum of the digits in an integer. 12 Any positive integer i can be expressed as i ϭ 2n k, where k is odd, that is, as a power of 2 times an odd number.